Six electric appliances of 100 watts each are used for 6 hours. The electrical energy consumed is:

3.6 k W h

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600 k W h

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3600 k W h

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60 k W h

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Solution

The correct option is A $3.6 k W h$
Total power,
P $= 100 \times 6 = 600 W$ ;
Total Time $= 6 h r$
As, Power $= \frac{E n e r g y}{T i m e}$
$E n e r g y = P o w e r \times T i m e = 600 \times 6 = 3600 W h = 3.6 k W h$

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