Question

Six faces of a die are as shown below.

If the die is rolled once, find the probability of -
(1) ‘A’ appears on upper face.
(2) ‘D’ appears on upper face.

Answer 1

Total number of faces = 6
(1)
Number of faces having A = 2
Therefore, required probability = $\frac{\mathrm{Number}\mathrm{of}\mathrm{faces}\mathrm{having}\mathrm{A}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{faces}}$
$$\begin{gathered} =\frac{2}{6} \\ =\frac{1}{3} \end{gathered}$$
Hence, the probability that ‘A’ appears on upper face is $\frac{1}{3}$.
(2)
Number of faces having D = 1
Therefore, required probability = $\frac{\mathrm{Number}\mathrm{of}\mathrm{faces}\mathrm{having}\mathrm{D}}{\mathrm{Total}\mathrm{number}\mathrm{of}\mathrm{faces}}$
$=\frac{1}{6}$
Hence, the probability that ‘D’ appears on upper face is $\frac{1}{6}$.