Six identical conducting rods are joined as shown in the figure. Points A and D are maintained at temperatures 200oC and 20oC respectively. The temperature of junction B will be
A
120oC
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B
100oC
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C
140oC
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D
80oC
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Solution
The correct option is C140oC Let the thermal resistance of each rod be R.
The two resistances connected along two paths from B to C are equivalent to 2R each and their parallel combination is R. Effective thermal resistance between B and D = 2R
Temperature of interface, θ=R1θ2+R2θ1R1+R2θ=R×20+2R×200R+2R=4203=140oC