Question

Six point charges are kept at the vertices of a regular hexagon of side $L$ and centre $O$, as shown in the figure. Given that $\frac{1}{4\pi {\epsilon }_0}\frac{q}{L^2}$, which of the following statement(s) is(are) correct?

• A. The electric field at $O$ is $6K$ along $OD$.
• B. The potential at $O$ is zero.
• C. The potential at all points on the line $PR$ is zero.
• D. The potential at all points on the line $ST$ is same.

Answer 1

The correct option is C The potential at all points on the line $PR$ is zero.

Given $k=\frac{1}{4\pi {\epsilon }_0}\frac{q}{L^2}$

(B) $v_0=\frac{1}{4\pi {\epsilon }_0}[\frac{q_A}{L}+\frac{q_B}{L}+......\frac{q_F}{L}]=0$ $[As{q}_A+q_B+.......+q_F=0]$

At line $PR,$ potential is same and is equal to zero.

Hence, solved.