Question

Six points were chosen on a circle and every possible chord was drawn. Two chords, which do not have the common points are named separately. How many pairs of separate chords exist in the situation described above?

• A. $26$
• B. $28$
• C. $30$
• D. $34$

Answer 1

Answer: (C)

$30$

We have to choose six points on circle and join them for every possible chord

So total number of ways is $6!$

But Two chord, which do not have common points i.e different chord

Hence Two chord has $4$ points So

Number of ways of different or separately chord is $\frac{6!}{4!}=30$