Six similar bulbs are connected as shown in the figure with a DC source of emf $E$ and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

4 : 9

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9 : 4

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1 : 2

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2 : 1

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Solution

The correct option is B 9 : 4

Case-I

$R_{e q 1} = \frac{2 R}{3} P_{e q 1} = \frac{3 E^{2}}{2 R}$

Case-II

$R_{e q 2} = \frac{R}{2} + R = \frac{3 R}{2} P_{e q 2} = \frac{E^{2}}{3 R / 2} = \frac{2 E^{2}}{3 R} ∴ P_{e q 1} : P_{e q 2} = 9 : 4$

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and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

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and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

Q. Three identical electric bulbs are connected parallel to each other. On connecting their combination across a source of emf having stabilized voltage and negligible resistance, all bulbs glow with full brightness. Suddenly a bulb fuses. The other bulbs will glow.

B_{1}, B_{2}

and

B_{3}

are three identical bulbs connected as shown in Figure 12.8. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
How much power is dissipated in the circuit when all the three bulbs glow together?

Question 28 (i)
$B_{1}, B_{2}$ and $B_{3}$ are three identical bulbs connected as shown in figure. When all the three bulbs glow, a current of 3A is recorded by the ammeter A.
(i) What happens to the glow of the other two bulbs when the bulb $B_{1}$ gets fused?

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Six similar bulbs are connected as shown in the figure with a DC source of emf E and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

The correct option is B 9 : 4 Case-I Req1 = 2R3 Peq1 = 3E22R Case-II Req2 = R2+R = 3R2Peq2 = E23R/2 = 2E23R∴ Peq1 : Peq2 = 9 : 4

Six similar bulbs are connected as shown in the figure with a DC source of emf $E$ and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

The correct option is B 9 : 4

Case-I

$R_{e q 1} = \frac{2 R}{3} P_{e q 1} = \frac{3 E^{2}}{2 R}$

Case-II

$R_{e q 2} = \frac{R}{2} + R = \frac{3 R}{2} P_{e q 2} = \frac{E^{2}}{3 R / 2} = \frac{2 E^{2}}{3 R} ∴ P_{e q 1} : P_{e q 2} = 9 : 4$