Six similar bulbs are connected as shown in the figure with a DC source of emf $E$ and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

4 : 9

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9 : 4

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1 : 2

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2 : 1

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Solution

The correct option is B 9 : 4

Case-I

$R_{e q 1} = \frac{2 R}{3} P_{e q 1} = \frac{3 E^{2}}{2 R}$

Case-II

$R_{e q 2} = \frac{R}{2} + R = \frac{3 R}{2} P_{e q 2} = \frac{E^{2}}{3 R / 2} = \frac{2 E^{2}}{3 R} ∴ P_{e q 1} : P_{e q 2} = 9 : 4$

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and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

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Question 3

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Six similar bulbs are connected as shown in the figure with a DC source of emf E and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

The correct option is B 9 : 4 Case-I Req1 = 2R3 Peq1 = 3E22R Case-II Req2 = R2+R = 3R2Peq2 = E23R/2 = 2E23R∴ Peq1 : Peq2 = 9 : 4

Six similar bulbs are connected as shown in the figure with a DC source of emf $E$ and zero internal resistance. The ratio of power consumption by the bulbs when (i) all are glowing and (ii) when two from section 'A' and one from section 'B' are glowing, will be

The correct option is B 9 : 4

Case-I

$R_{e q 1} = \frac{2 R}{3} P_{e q 1} = \frac{3 E^{2}}{2 R}$

Case-II

$R_{e q 2} = \frac{R}{2} + R = \frac{3 R}{2} P_{e q 2} = \frac{E^{2}}{3 R / 2} = \frac{2 E^{2}}{3 R} ∴ P_{e q 1} : P_{e q 2} = 9 : 4$