Question

Six symmetrical dice are thrown simultaneously. The probability of having different points on them is

• A. $\frac{1}{6}$
• B. $\frac{1}{36}$
• C. $\frac{6!}{6^6}$
• D. $\frac{1}{18}$

Answer 1

The correct option is C $\frac{6!}{6^6}$

Total number of outcomes will be $6^6$
The number of ways in which we can have different points on each of them is $6!$ ways.
The required probability $=$ $\frac{6!}{6^6}$