Question

Six unbiased coins are tossed the probability of obtaining atleast two heads is

• A. $\frac{50}{64}$
• B. $\frac{55}{64}$
• C. $\frac{57}{64}$
• D. $\frac{60}{64}$

Answer 1

Answer: (C)

$\frac{57}{64}$

To find the probability of finding atleast two heads, we will find out the probability of one head and zero heads and subtract it from $1$.
Required Probability $=1-\frac{(6C_0+6C_1)}{2^6}=\frac{57}{64}$