Six Xs are to be placed in the squares of the figure given above such that each row contains at least one X. The number of ways this can be done is
A
18
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B
22
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C
26
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D
30
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Solution
The correct option is A 26 Favorable cases = Total cases − Unfavorable cases =8C6− 2 = 26 Unfavorable cases =two cases of the first row empty and last row empty.