Six Xs have to be placed in the squares of figure below in such a way that each row contains at least one X. In how many different ways can this be done?
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Solution
As all the X's are identical, the question is of selection of 6 squares from 8 squares, so that no row remains empty. Here R1 has 2 squares, R2 has 4 squares, and R3 has 2 squares. The selection scheme is as follows:
R1
R2
R3
1
4
1
1
3
2
2
3
1
2
2
2
Therefore, number of selection is 2C1×4C4×2C1+2C1×4C3×2C2+2C2×4C3×2C1+2C2×4C2×2C2=4+8+8+6=26