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Question
Six years ago a man was three times as old as his son. In 6 years time, he will be twice as old as his son. Find their present ages
Six years ago a man was three times as old as his son. In 6 years time, he will be twice as old as his son. Find their present ages
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Solution
The correct option is C 42,18
Let the present ages of father and son be x and y, respectively.
As per the problem, six years ago,
(x−6)=3(y−6)
Six years later, (x+6)=2(y+6)
Solving these two equations, we get father's age is 42 years, and son's age is 18 years.
Let the present ages of father and son be x and y, respectively.
As per the problem, six years ago,
(x−6)=3(y−6)
Six years later, (x+6)=2(y+6)
Solving these two equations, we get father's age is 42 years, and son's age is 18 years.
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