Question

Sixteen resistors, each of resistance $16\Omega$ are connected in the circuit as shown in Figure. The net resistance between $A$ and $B$ is

• A. $1\Omega$
• B. $2\Omega$
• C. $3\Omega$
• D. $\Omega$

Answer 1

The correct option is C $3\Omega$

Here the four resistors with resistance $R=16\Omega$ on each side are in parallel. The equivalent resistance for each side is $R_{eq}=(1/R+1/R+1/R+1/R{)}^{-1}=R/4$

$\therefore R_{AB}=\frac{\left(3R/4\right)\left(R\right)}{\left(3R/4\right)+R}=\frac{3R}{16}=\frac{3\left(16\right)}{16}=3\Omega$