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Areas of Combination of Plane Figures

Size of a til...

Question

Size of a tile is $9$ inches by $9$ inches. The number of tiles needed to cover a floor of $12$ feet by $18$ feet is

A

384

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B

32

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C

24

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D

216

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Solution

The correct option is A $384$
Number of tiles $= \frac{A r e a o f f l o o r}{A r e a o f 1 t i l e}$

$= \frac{12 \times 12 \times 18 \times 12}{9 \times 9} = 384$

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