Question

Sketch a graph and represent the zeroes of the quadratic polynomial for the equation $y=x^2+2x-3$.

Answer 1

Factor of $x^2+2x-3=(x+3)(x-1)$
Plotting $(-3,0)(-2,-3)(-1,-4)(1,0$) and joining them.
Here, the graph cuts $x$-axis at two distinct points $A$ and $A^{\prime }$.
The $x$-coordinates of $A(-3,0)$ and $A^{\prime }(1,0)$ are the two zeroes of the quadratic polynomial $y=x^2+2x-3$.