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Question

Sketch the following graphs:

(i) y=cosx+π4
(ii) y=cosx-π4
(iii) y = 3 cos (2x − 1)
(iv) y=2 cosx-π2

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Solution

(i)
y=cosx+π4 y-0=cosx+π4 ...(i)On shifting the origin at -π4,0, we get:x=X-π4 and y=Y+0On subsitituting the values in (i), we get:Y=cosXThen, we draw the graph of Y=cosX and shift it by π4 to the left.
Then, we obtain the following graph:


(ii)
y=cosx-π4 y-0=cosx-π4 ...(i)On shifting the origin at π4,0, we get:x=X+π4 and y=Y+0On subsitituting the values in (i) we get:Y=cosXThen, we draw the graph of Y=cosX and shift it by π4 to the right.
Then, we obtain the following graph:


(iii)
y=3cos2x-1 y-0=3cos2x-12 ...(i)On shifting the origin at 12,0, we have:x=X+12 and y=Y+0On subsitituting the values in (i), we get:Y=3cos2XThen, we draw the graph of Y=3cos2X and shift it by 12 to the right.
Then, we obtain the following graph:


(iv)
y=2cosx-π2 y-0=2cosx-π2 ...(i)On shifting the origin at π2,0, we get:x=X+π2 and y=Y+0On subsitituting the values in (i), we get:Y=2cosXThen, we draw the graph of Y=cosX and shift it by π2 to the right.
Then, we obtain the following graph:


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