Sketch the graph of the following functions :
y=sin2x
We know that,
y=sin2x=1−cos2x2=12−12 cos 2x
We have,
y=12−12 cos =2x
⇒y−12=−12 cos 2x ...(i)
Shifting the origin at (0,−12), we obtain
x=X,,y=Y+12
Substituting these values in (i), we get
Y=−12 cos2x.
Thus we draw the grpah of Y=cos2X, adjust the maximum and minimum values to 12 and - 12 and shift it by 12 up to get the required graph.