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Question

Sketch the graph of the following functions :
y=sin2x

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Solution

We know that,
y=sin2x=1cos2x2=1212 cos 2x
We have,
y=1212 cos =2x
y12=12 cos 2x ...(i)
Shifting the origin at (0,12), we obtain
x=X,,y=Y+12
Substituting these values in (i), we get
Y=12 cos2x.
Thus we draw the grpah of Y=cos2X, adjust the maximum and minimum values to 12 and - 12 and shift it by 12 up to get the required graph.


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