wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Sketch the region bounded by the curves y=x2 & y=2/(1+x2). Find the area:

A
π23
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
B
π13
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π53
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
π73
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is A π23
y=x2 and y=21+x2
Therefore
x2=21+x2
x4+x22=0
(x2+2)(x21)=0
Now x is real.
Therefore x2+2=0 is not possible.
Hence
x=±1.
Hence the required area is
=11x221+x2
=210x221+x2
=2[x332tan1(x)]10
=2[132.π4]
=|23π|
=π23 sq.units.

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area under the Curve
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon