Question

Sketch the zeros of the given linear polynomial: $x-3y=15$

Answer 1

$x-3y=15$
$x-15=3y$
$y=\frac{x-15}{3}$
Plotting $(0,-5),(15,0)$ and joining them, we get another straight line.
The graph of $x-3y=15$ intersect the $x$-axis at $(15,0)$. Hence the zero of $x-3y=15$ is $(15,0)$ as it intersects at $x$-axis at $(15,0)$.