Consider the given equation,
1x−2+2x−2=16 , where x≠0,1,2
1x−2+2x−2=16
1x−2[1+2]=16
3x−2=16
x−2=6×3=18
x=20
Solve each of the following quadratic equations: 1x−2+2x−1=6x,x≠0,1,2