Question

Slolve for $x:-$

$\frac{1}{x-2}+\frac{2}{x-2}=\frac{6}{x}$, where $x\ne 0,1,2$

Answer 1

Consider the given equation,

$\frac{1}{x-2}+\frac{2}{x-2}=\frac{1}{6}$ , where $x\ne 0,1,2$

$\frac{1}{x-2}+\frac{2}{x-2}=\frac{1}{6}$

$\frac{1}{x-2}[1+2]=\frac{1}{6}$

$\frac{3}{x-2}=\frac{1}{6}$

$x-2=6\times 3=18$

$x=20$

Hence, this is the answer.