Question

Slope of a line whose inclination is ${60}^{\circ }$ is ____.

• A. 0
  
• B. $\frac{1}{\sqrt{3}}$
  
• C. $\sqrt{3}$
  
• D. 1

Answer 1

The correct option is C

$\sqrt{3}$

Let m be the slope of of the line
Given: Angle of inclination is ${60}^{\circ }$
$m=tan\theta$
$\therefore m=tan\left({60}^{\circ }\right)m=\sqrt{3}$ (since $tan{60}^{\circ }=\sqrt{3}$)