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Question

Slope of line joining points (5,3) and (k2,k+1) is 12 then k is

A
1
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B
1±2
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C
2±1
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D
1±2
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Solution

The correct option is C 1±2
y=mx+c=>3=12×5+c=>2c=1=>c=12y=mx+c=>k+1=12k2+12=>2k+2=k2+1=>k22k1=0=>k=2±4+42=2±222=1±2

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