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Arrhenius Equation

Slope of stra...

Question

Slope of straight line in graph-B is -6670, the activation energy for the reaction is :

127.71 J

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127.71 k J

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12.771 J

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12.771 k J

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Solution

The correct option is C $127.71 k J$
The expression for the slope of the graph -
$S l o p e = - \frac{E_{a}}{2.303 R} = - 6670.$

Hence, the expression for the activation energy becomes $E_{a} = 6670 \times 2.303 R = 6670 \times 2.303 \times 8.314 = 127710 J = 127.71 k J .$

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