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Question

Slope of the common tangent to the ellipses x2a2+b2+y2b2=1,x2a2+y2a2+b2=1 is:

A
2ab
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B
2ba
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C
ab
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D
ba
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Solution

The correct option is B ab
Condition of common tangent will be c2=(a2+b2)m2+b2=a2m2+(a2+b2)
Therefore, m2=a2b2
m=ab
Ans: C

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