Slope of the line perpendicular to the line with equation $y = 6 x + 7$ is _____

- 6

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(\frac{1}{6})

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(\frac{- 1}{6})

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6

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Solution

The correct option is B $(\frac{- 1}{6})$
Let the slope of the required line be $m_{1}$ .
The slope of line $y = 6 x + 7$ is $m_{2}$ $= 6$ .
For the given two lines to be perpendicular we have $m_{1} \times m_{2} = 1$
$(m_{1} \times m_{2} = 1)$
$(m_{1} \times 6 = 1)$ or $m_{1} = \frac{1}{6}$
The slope of the line perpendicular to the given line is $m_{1} = \frac{1}{6}$ .

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