Question

Slope of the line whose inclination is ${120}^o$

• A. $-\frac{1}{\sqrt{3}}$
• B. $\frac{1}{\sqrt{3}}$
• C. $-\sqrt{3}$
• D. $\frac{1}{2}$

Answer 1

The correct option is C $-\sqrt{3}$

Given the inclination $\left(\theta \right)$ of the line is ${120}^o$.

Then slope will be $\tan \theta =\tan {120}^o=-\sqrt{3}$.