Sm2+, Eu2+ and Yb2+ ions in solutions are good reducing agents but an
aqueous solution of Ce4+ is a good oxidizing agent. Why?

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Solution

All these are belong to Lanthanoid series in which the +3 state is the most stable. All the ions tend to acquire +3 oxidation state, Np⁺⁴ or Ce⁺⁴does so by undergoing reduction and thus a good oxidising agent. Sm²⁺, Eu²⁺ and Yb²⁺ ions undergo oxidation to acquire the stable state and are thus good reducing agents.

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