Question

Small Quantities of solutions of compounds TX, TY and TZ are put into separate test tubes containing X,Y and Z solutions. TX does not react with any of these. TY reacts with both X and Z. TZ reacts with X. The decreasing order of oxidation of anions $X^{-},Y^{-},Z^{-}$ is :

• A. $Y^{-},Z^{-},X^{-}$
• B. $Z^{-},X^{-},Y^{-}$
• C. $Y^{-},X^{-},Z^{-}$
• D. $X^{-},Z^{-},Y^{-}$

Answer 1

The correct option is A $Y^{-},Z^{-},X^{-}$

TX does not react with any solution. This means that $X^{-}$ is easily oxidized. TY reacts with X and Z. This means $Y^{-}$ is oxidized by both.
$(Y^{-}+X\to Y+X^{-});$

$(Y^{-}+Z\to Y+Z^{-})$
TZ reacts with X only. This means $Z^{-}$ is less easily oxidized than $Y^{-}$. Thus, decreasing order of oxidation of anions $X^{-},Y^{-},Z^{-}$ will be: $Y^{-},Z^{-},X^{-}$