$S n$ dissolve in hot $N a O H$ solution . The chemical reaction is as follows:
$S n + 2 N a O H + H_{2} O \to N a_{2} S n O_{3} + H_{2}$
If true enter 1, else 0.

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Solution

Reactions of Sn with hot NaOH:
$S n + 2 N a O H + H_{2} O \to N a_{2} S n O_{3} + H_{2}$
Or
$S n + 2 N a O H + 4 H_{2} O \to N a_{2} [S n (O H)_{6}] + 2 H_{2}$
Similarly with $P b$ :
$P b + 2 N a O H + H_{2} O \to N a_{2} P b O_{3} + H_{2}$
Or
$P b + 2 N a O H + 4 H_{2} O \to N a_{2} [P b (O H)_{6}] + 2 H_{2}$
Hence, the statement is ture.

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