SnCl 2- A - SnS -2 HClSnS - NH 42 S - S - BHere A and B is-A- S2 HB- H2 S- N2- S n O4D- N H42 S n S3

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Amphoteric Metals Reaction

SnCl 2+ A → S...

Question

$S n C l_{2} + A \to S n S + 2 H C l$

$S n S + (N H_{4})_{2} S + S \to B$

Here A and B is:

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Similar questions

$S n C l_{2} + 2 N a O H \to A + 2 N a C l$

$A + 2 N a O H \to B + 2 H_{2} O$

Identify A and B

H g C l_{2}

S n C l_{2}

S n C l_{2}

S n {C l}_{2}

S n {C l}_{2} + {C l}_{2} ⟶ S n {C l}_{4}

When Sn reacts with calculated amount of $H g C l_{2}$ and excess $H g C l_{2}$ , then the product will be respectively.

The correct representation for solubility product of SnS₂ is:

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