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Zinc Ion

SnCl2 acts as...

Question

$S n C l_{2}$ acts as a reducing agent because :

S n C l_{2}

can accept electrons readily

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S n^{2 +}

is more stable than

S n^{4 +}

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S n^{4 +}

is more stable than

S n^{2 +}

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S n^{2 +}

can be easily converted to metallic tin

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Solution

The correct option is C $S n^{4 +}$ is more stable than $S n^{2 +}$
● SnCl2 acts as reducing agent because -
-Sn has electronic configuration [Kr] 4d10 5s2 5p2.
-Sn doesn't exhibit inert pair effect & thus higher oxidation state is more stable.
-Sn4+ is more stable than Sn2+.
-SnCl2 readily reacts with other compounds & get converted to stable SnCl4.
-During the reaction, SnCl2 gets oxidised while other compound is reduced.
-Thus, SnCl2 is a good reducing agent.
So option (c) is correct

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H A s O_{2} + S n^{2 +} \to A s + S n^{4} + H_{2} O

[1] P b^{2 +} > P b^{4}, S n^{2 +} > S n^{4 +}

[2] P b^{2 +} < P b^{4}, S n^{2 +} < S n^{4 +}

[3] P b^{2 +} > P b^{4}, S n^{2 +} < S n^{4 +}

[4] P b^{2 +} < P b^{4}, S n^{2 +} > S n^{4 +}

[5] S n^{2 +} < P b^{2 +}, S n^{4 +} > P b^{4 +}

[6] S n^{2 +} < P b^{2 +}, S n^{4 +} < P b^{4 +}

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