MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Reactivity Towards Halogens

SnCl2 is a be...

Question

$S n C l_{2}$ is a better reducing agent than $H g C l_{2}$ .

A

True

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

B

False

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A True
In $S n C l_{2}$ , Sn in II oxidation state and it is more stable in higher oxidation so it has tendency to loose electron and form Sn IV so $S n C l_{2}$ is better reducing agent.
As Hg has very low tendency to form higher oxidation state.

Suggest Corrections

thumbs-up

0

Similar questions

Q. Assertion :Statement 1 :

H g C l_{2}

S n C l_{2}

exist together in an aqueous solution. Reason: Statement 2 :

S n C l_{2}

is a strong reducing agent.

S n C l_{2}

is a reducing agent. Reason:

S n C l_{2}

F e C l_{3}

F e C l_{2}

H g C l_{2}

H g

.

H g C l_{2}

S n C l_{2}

can not exist together in an aqueous solution. Reason:

S n C l_{2}

is a strong reducing agent because Sn shows inert pair effect.

S n C l_{2}

acts as a reducing agent because :

Q. Which of the following statements is correct for compound

H g C l_{2}, S n C l_{2}

F_{2} O

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Chemical Properties of Carbon Family

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Reactivity Towards Halogens

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon