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Redox Reactions

SO2-3 and S...

Question

$S O_{3}^{2 -}$ and $S O_{4}^{2 -}$ both give white precipitate with $B a C l_{2}$ solution. Scheme to detect $S O_{3}^{2 -}$ in presence of $S O_{4}^{2 -}$ is given below. If true enter 1, if false enter 0.
$B a S O_{4}$ is insoluble in conc. HCl while $B a S O_{4}$ remains soluble. Separate $B a S O_{4}$ and add $B r_{2}$ water into filtrate. $S O_{3}^{2 -}$ is oxidised to $S O_{4}^{2 -}$ and gives white precipitate of $B a S O_{4}$ .

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Solution

$B a S O_{4}$ is insoluble in conc. HCl, while $B a S O_{3}$ remains soluble.
Separate $B a S O_{4}$ and add $B r_{2}$ water into filtrate which contains $B a S O_{3}$ .
$S O_{3}^{2 -}$ oxidized to $S O_{4}^{2 -}$ (with oxygen generated by the reaction of bromine with water) and gives white precipitate of $B a S O_{4}$ .
Thus, sulphite can be detected in presence of sulphate.
$B r_{2} + H_{2} O ⟶ 2 H B r + O$
$B a S O_{3} + O ⟶ B a S O_{4} ↓$

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