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Valency and Oxidation States

SO2 is oxidis...

Question

$S O_{2}$ is oxidised to ${S O_{4}}^{2 -}$ in acid medium. Calculate equivalent mass of $S O_{2}$ .

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Solution

$S_{2} (g) + 2 H_{2} O \to_{2} + 6 - 8 S O_{4} + 2 H^{+} + 2 e^{-}$
Change in oxidation number of sulphur $= 6 - 4 = 2$
Equivalent mass of $S O_{2} = \frac{M o l e c u l a r m a s s}{2} = \frac{64}{2} = 32$ .

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Q. Equivalent weight of

S O_{2}

is found to be 32 in a reaction taking place in acidic medium. This reaction is represented as

S O_{2} + 2 H_{2} O \to S O_{4}^{2 -} + 4 H^{+} + 2 e^{-}

State whether the given reaction take place in backward direction or forward direction?

Balance the following redox reaction in acidic medium:

M n O_{4}^{-} + S O_{2} ⟶ S O_{4}^{2 -} + {M n}^{2 +}

Q. Equivalent mass of oxidising agent in the reaction,

S O_{2} + 2 H_{2} S \to 3 S + 2 H_{2} O

is____________.

Q. The equivalent mass of oxidising agent in the following reaction is :

S O_{2} + 2 H_{2} S ⟶ 3 S + 2 H_{2} O

Q. The mixture of

C u S

(molar weight =

M_{1}

C u_{2} S

(molecular weight =

M_{2}

) is oxidised by

K M n O_{4}

(molecular weight =

M_{4}

) in acidic medium, the product obtained are

C u^{2 +}

S O_{2 +}

. The equivalent weights of

C u S, C u_{2} S

K M n O_{4}

respectively, are :

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