Soapy water drips from a capillary tube. When the drop breaks away, the diameter of its neck is $D$ . The mass of the drop is $m$ . Find the surface tension of soapy water?-

\frac{m g}{π^{2} D}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m g}{π D^{2}}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{m g}{π D}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{m g}{2 π D}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is C $\frac{m g}{π D}$
We know that
$\begin{matrix} f_{T} & = T L [\begin{matrix} T = surface Tension L = length in contact] \end{matrix} if Body is in equilibrium \end{matrix}$
$f_{T} = m_{g}$
$T x π D = m g (D =$ Diameter )
$T = \frac{m g}{π D}$

Answer: $(C) \frac{m g}{π D}$

Suggest Corrections

Similar questions

Q. A capillary tube is vertically partly dipped in water shows capillary rise. If the mass of water in capillary rise is

22 m g

. What is the diameter of tube (

T = 70 d y n e s / c m

)

Q. An open capillary tube contains a drop of water. When the tube is in its vertical position, the drop forms a column with a length of

2.98 c m

. The internal diameter of the capillary tube is

1 m m

. The radii of curvature of the upper meniscus (in mm)is

\frac{x}{4}

. Consider the wetting to be complete. Surface tension of water

= 0.0075 N / m

. Find the value of x.

Q. An open capillary tube contains a drop of water. When the tube is in its vertical position, the drop forms a column with a length of

2 c m

. The internal diameter of the capillary tube is

1 m m

. Determine the radii of curvature of the upper and lower meniscus in each case. Consider the wetting to be complete. Surface tension of water

= 0.0075 N / m

A vertical capillary with inside diameter 0.50mm is submerged in to water so that the length of its part emerging outside the water surface is equal to 25mm.Find the radius of curvature of the meniscus. Surface tension of water is $73 \times 10^{- 3} N / m (g = 9.8 m / s^{2})$

Q. A simple pendulum of mass m is performing vertical circular motion with its velocity at the highest point being V

= \sqrt{2 g l}

where l is the length of the string. Find the tension in the string when it reaches the lowest point.

Join BYJU'S Learning Program

Soapy water drips from a capillary tube. When the drop breaks away, the diameter of its neck is D. The mass of the drop is m. Find the surface tension of soapy water?-

The correct option is C mgπDWe know thatfT=TL[T= surface Tension L= length in contact ] if Body is in equilibrium fT=mgTxπD=mg(D= Diameter )T=mgπD Answer: (C)mgπD

Soapy water drips from a capillary tube. When the drop breaks away, the diameter of its neck is $D$ . The mass of the drop is $m$ . Find the surface tension of soapy water?-