Question

$Sodium-24$, a radioactive isotope having half of 15 hours is used medically in blood studies and it decays by beta decay. What would be the product of the radioactive decay of $Na-24?$

• A. $F-20$
• B. $Ne-24$
• C. $Ne-23$
• D. $Na-23$
• E. $Mg-24$

Answer 1

The correct option is E $Mg-24$

beta decay $(\beta -decay)$ is a type of radioactive decay in which a beta particle (fast energetic electron or positron) is emitted from an atomic nucleus, transforming the original nuclide to an isobar.

There is an increase in atomic number by $1$ in $\beta$ emissionc So the product of the radioactive decay of $Na-24$ is ${}_{24}Mg$ as follows:

${}_{11}^{24}Na{\to }_{12}^{24}Mg{+}_{-1}{\beta }^0$

So option E is correct