Sodium acetate on heating with soda lime produce :

C H_{4}

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C_{2} H_{6}

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C_{3} H_{8}

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C_{2} H_{4}

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Solution

The correct option is A $C H_{4}$
${C H}_{3} C O O N a + N a O H C a O / h e a t - ----- \to {C H}_{4} + {N a}_{2} {C O}_{3}$
This is a decarboxylation reaction to produce alkane as a product.

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Similar questions

Which of the following will give addition reactions and why ?
$C_{4} H_{10}, C_{2} H_{6}, C_{2} H_{4}, C H_{4}, C_{3} H_{8}, C_{3} H_{4}$

C

C H_{4}, C_{2} H_{6}, C_{3} H_{8}, C_{2} H_{4}, C_{2} H_{2}, H_{2} C_{2} O_{4}

C O_{2}

C_{2} H_{6}

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