Sodium and copper have work functions 2.3eV and 4.5eV respectively. Then the ratio of their threshold wavelengths is nearest to

1 : 2

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4 : 1

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2 : 1

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1 : 4

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Solution

The correct option is C
2 : 1

$W_{0} \propto \frac{1}{λ} \Rightarrow \frac{λ_{1}}{λ_{2}} = \frac{(W_{0})_{2}}{(W_{0})_{1}} = \frac{4.5}{2.3} = \frac{2}{1}$

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Sodium and copper have work functions 2.3eV and 4.5eV respectively. Then the ratio of their threshold wavelengths is nearest to

The correct option is C 2 : 1 W0∝1λ⇒λ1λ2=(W0)2(W0)1=4.52.3=21

The correct option is C
2 : 1

$W_{0} \propto \frac{1}{λ} \Rightarrow \frac{λ_{1}}{λ_{2}} = \frac{(W_{0})_{2}}{(W_{0})_{1}} = \frac{4.5}{2.3} = \frac{2}{1}$