Sodium borate on hydrolysis will give:

Metaborate

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Boride

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Boric acid

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B_{2} O_{3}

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Solution

The correct option is C Boric acid
Boric acid may be prepared by reacting borax (sodium tetraborate decahydrate) with a mineral acid, such as $H C l$ :
$N a_{2} B_{4} O_{7} \cdot 10 H_{2} O$ + $2 H C l$ → $4 B (O H)_{3}$ + $2 N a C l$ + $5 H_{2} O$

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