Sodium burns in dry air to ordinarily give:

N a_{2} O

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N a_{2} O_{2}

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N a O_{2}

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N a_{3} N

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Solution

The correct option is A $N a_{2} O$
Sodium burns in dry air to give $N a_{2} O$ .
$2 N a + \frac{1}{2} O_{2} \to N a_{2} O$

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