Sodium burns in excess air to give mainly:

N a_{2} O

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N a O_{2}

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N a_{2} O_{2}

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N a H

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Solution

The correct option is C $N a_{2} O_{2}$
Sodium burns in excess air to form peroxide ( $N a_{2} O_{2}$ ).
$2 N a + O_{2} \to N a_{2} O_{2}$

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