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Question

Sodium Carbonate reacts with dilute sulphuric acid to give the respective salt,water and carbon dioxide.Calculate the mass of the pure salt formed when 300g of sodium carbonte of 80% purity reacts with dilute sulphuric acid.

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Solution

The chemical formula for the reaction is as follows; Na2CO3 + H2SO4 ==> Na2SO4 + H2O + CO2 Iam here providing the steps to calculate the mass of salt. mols Na2CO3 if pure = grams/molar mass = 300/142 = about 2 but that's an estimate. It's only 80% so 2 x 0.80 = about 1.6 g Na2SO4 actually there. Convert mols Na2CO3 to mols Na2SO4. Then g Na2SO4 = mols Na2SO4 x molar mass Na2CO3 Please go through the steps to calculate. The answer is321.51gm

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