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Stoichiometric Calculations

Sodium chlori...

Question

Sodium chloride ( $N a C l$ ) reacts with silver nitrate ( $A g N O_{3}$ ) to produce silver chloride ( $A g C l$ ) and sodium nitrate ( $N a N O_{3}$ ). The weight of silver nitrate reacts with 1 mol of sodium chloride is _________ .

A

170

g

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B

85

g

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C

340

g

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D

240

g

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Solution

The correct option is A $170$ g
Reaction:
$N a C l + A g N O_{3} \to A g C l + N a N O_{3}$
1 mole of sodium chloride reacts with 1 mole of silver nitrate to form 1 mole of silver chloride and one mole of silver nitrate.
58.5 g of sodium chloride reacts with 170 g of silver nitrate to form 143.5 g of silver chloride and 85 g of sodium nitrate.

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Similar questions

Sodium chloride (

N a C l

) reacts with silver nitrate (

A g N O_{3}

) to produce silver chloride (

A g C l

) and sodium nitrate (

N a N O_{3}

). The correct balanced chemical equation is :

Q. Sodium chloride (

N a C l

) reacts with silver nitrate (

A g N O_{3}

) to produce silver chloride (

A g C l

) and sodium nitrate (

N a N O_{3}

). The law which satisfies this equation is ___________________ .

Q. What Massi of silver nitrate will react with 8.85 g of Nacl to produce 14.35 of silver chloride and 8.5g of sodium nitrate?

Q. What mass of silver nitrate will react with

5.85 g

of sodium chloride to produce

14.35 g

of silver chloride and

8.5 g

of sodium nitrate. If the law of conservation of mass is true?

10 g NaCl solution is mixed with 17 g of silver nitrate solution. Calculate the weight of silver chloride precipitated.
AgNO₃ + NaCl $\overset{}{\to}$ AgCl + NaNO₃ [Ag = 108]

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