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Question

Sodium does not normally react with


A

Ammonia Gas

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B

But-2-yne

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C

Ethyne

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D

Propyne

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Solution

The correct option is B

But-2-yne


The correct answer is option B.

Explanation of correct answer:-

  • The compound should have acidic hydrogen in order to react with sodium metal.
  • Since, But-2-yne lacks terminal acidic hydrogen so it does not react with Na(sodium metal).
  • In But-2-yne, both the carbons involved in triple bonding do not have a hydrogen atom and the terminal carbon atoms are 'sp3' hybridized that means it has less ‘s’ character in them, therefore the tendency to donate H+ ion will be less.
  • Hence but-2-yne has 0 acidic hydrogen and does not react with sodium metal.

Explanation of incorrect answers:-

Option A

  • Ammonia gas reacts with Na(sodium metal) to form sodamide (NaNH2) with the release of hydrogen gas.
  • Sodium ionises in liquid ammonia, producing a Na+ ion and an electron. Ammonia is used to dissolve the electron.

Option C

  • Ethyne is an alkyne that has acidic terminal hydrogen required to react with sodium metal (Na).
  • Ethyne reacts with sodium metal and sodamide to form sodium acetylide with the liberation of dihydrogen gas.

Option D

  • Propyne has acidic terminal hydrogen.
  • The reduction of propyne with sodium in liquid ammonia gives prop-1-ene.

Therefore, option (B) is the correct answer.


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