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Valency and Oxidation States

Sodium forms ...

Question

Sodium forms $N a^{+}$ ion but it does not form $N a^{2 +}$ because?

Very low value of

I E_{1}

and

I E_{2}

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Very high value of

I E_{1}

and IE

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Low value of

I E_{1}

and low value of

I E_{2}

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Low value of

I E_{1}

and high value of

I E_{2}

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Solution

The correct option is B Low value of $I E_{1}$ and high value of $I E_{2}$
Na (sodium) has electron configuration [2, 8, 1]. Therefore, it has 1 valence electron, which it ideally needs to remove in order to be “stable” ideal gas configuration. But removing second electron from sodium implies that removing electron from a “stable” ideal gas configuration which requires high energy therefore, sodium forms $N a^{+}$ ion but not $N a^{2} +$ because low IE1 and high IE2

option (D) is correct.

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