Sodium hydride reacts with water to yield:

N a O H

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$H_{2} O_{2}$

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$H_{2} O$

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$H_{2}$

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Solution

The correct options are
A $N a O H$
D
$H_{2}$

When metal hydrides of group 1 elements react with water, hydrogen gas escapes from the solution while metal hydroxides are found in the solution.
$N a H (s) + H_{2} O (l) \to N a O H (a q)$ + $H_{2} (g)$

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