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Reactivity with Air and Water (Group 2)

Sodium loses ...

Question

Sodium loses its lustre on exposure to air due to formation of:

N a_{2} O

N a O H

and

N a_{2} C O_{3}

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N a_{2} O

and

N a O H

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N a_{2} O

and

N a_{2} C O_{3}

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N a O H

and

N a_{2} C O_{3}

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Solution

The correct option is C $N a_{2} O$ , $N a O H$ and $N a_{2} C O_{3}$
Sodium loses its lustre on exposure to air due to formation of $N a_{2} O$ , $N a O H$ and $N a_{2} C O_{3}$
Sodium on exposure to air catches the $O_{2}$ , $H_{2} O$ (vapour) and $C O_{2}$ and forms $N a_{2} O$ , $N a O H$ and $N a_{2} C O_{3}$
$4 N a + O_{2} \to 2 N a_{2} O$
$N a_{2} O + C O_{2} \to 2 N a_{2} C O_{3}$
$2 N a + 2 H_{2} O \to 2 N a O H + H_{2}$
Hence option $A$ is correct.

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