Question

Sodium metal crystallises in bcc structure with the edge length of unit cell $4.29\times {10}^{-8}cm$. Calculate the radius of sodium atom.

Answer 1

$a=4.29\mathring{A}$ (given)

In BCC structure $4r=a\sqrt{3}$ (Along body diagonal)

$r=\frac{a\sqrt{3}}{4}=1.857\mathring{A}$