Question

Sodium ordinarily does not show an oxidation state of +2, because of its

• A. High first ionization potential
• B. High second ionization potential
• C. Large ionic radius
• D. High electronegativity

Answer 1

The correct option is B High second ionization potential

The electonic configuration of Na is 2,8,1 the last orbital can have the maximum of 8 electrons. Instead of adding 7 electrons to become stable, Na looses one electron; get the configuration of 2,8 and become stable. Na after loosing one electron it becomeNa+.

The electronic configuration of $N{a}^{+}$ 2,8 which is more stable than that of Na. Hence it isn't afford to loose one more electron and become unstable. (2,7 is unstable electronic configuration )
So sodium doesn't have a $N{a}^{2+}$ ion.